river

[redhat007]

i have used WOA2009 for providing climatology file. its monthly data has temp_time and salt_time have as 15, 46,75,106,136,167,197,228,259,289,320 and 350 days. But i am not sure that for monthly river runoff data it is correct to set river_time to 0,31,59,90,120,151,181,212,243,273,304,334 days or time such as climatology time ( temp_time or salt_time).
I become appreciate to receive your note

cheers
redhat

P.C
with regard that roms is able to interpolate data in time, my believe is that when i use river_time as 0, 31 .. ,304, roms will use first runoff data from 0 to 31 days , second data from 32 to 59 days and go on. would you please tell me if i am on wrong?

[kate]

You can set your river_time to 0,31,59,90,120,151,181,212,243,273,304,334 days if that is what you want. ROMS can interpolate both river_time and salt_time independently.

[redhat007]

dear kate
i change my question. For monthly river data which one is corretc: sets its time to 0,31,59,90,120,151,181,212,243,273,304,334 or 15, 46,75,106,136,167,197,228,259,289,320, 350 days?
Thanks again
redhat

[kate]

For monthly fields, I usually go for something like the latter, but I want my year to last 365.25 days (cycle_length). For example:

Code: Select all

	double runoff_time(runoff_time) ;
		runoff_time:long_name = "time" ;
		runoff_time:units = "days since 1900-01-01 00:00:00" ;
		runoff_time:cycle_length = 365.25 ;
 runoff_time = 15.21875, 45.65625, 76.09375, 106.53125, 136.96875, 167.40625, 
    197.84375, 228.28125, 258.71875, 289.15625, 319.59375, 350.03125 ;

[redhat007]

thanks for your reply.
Second question:For monthly climatology data which its data is: 16 january, 16 February, 17 march, 17 April, and 17th of next months, length_cycle is 365 or 365.25?
many thanks
redhat

[kate]

How many years are you running and what are you doing about leap years? We run multiple decades with leap years so pick 365.25 as a cycle length.